RC Time Constant Calculator

Enter R and C to get τ, the practical 5τ settle time, the voltage at any instant, and the time to any target — the exponential that governs delays and filters.

RC Time Constant Calculator inputs

Leave blank to skip the instantaneous voltage.

Leave blank to skip the time-to-target.

Last updated: 2026-09-28

How the calculation works

  • τ = RC is the circuit's natural clock: 63.2% charged at 1τ, 86.5% at 2τ, 99.3% at 5τ.
  • The exponential curve answers 'voltage after t' and its inverse 'time to reach V'.
  • 5τ is the engineering 'fully settled' milestone used in debounce and delay design.

Formula

τ = R × C
V(t) = V₀ × (1 − e^(−t/τ))
t(target) = −τ × ln(1 − V/V₀)
Formula variables
SymbolMeaningUnit
τTime constants
tElapsed times

Worked example

10 kΩ × 10 µF: τ = 100 ms — 63.2% charged at 100 ms, practically full at 500 ms. To reach 90%: t = −0.1 × ln(0.1) = 230 ms. The same circuit is a low-pass filter with f₋₃dB = 1/(2πRC) = 1.59 Hz.

Interpreting the result

The RC exponential is everywhere: switch debounces, reset delays, LED fade, analog filtering and timing circuits all live on this curve. Design lever: pick the time constant you need and solve for R×C, then choose R to respect the currents (high R saves power but invites noise; low C costs money and space). The same τ defines the filter corner f = 1/(2πRC) — the capacitor that delays also filters.

Assumptions

  • Ideal RC — no source impedance, no capacitor ESR or leakage.
  • Single charging (or discharging) event from a fixed supply.

Limitations

  • Electrolytic capacitor tolerance (±20%) shifts real timing — design with margin.
  • Repeated switching (PWM) behavior needs the steady-state ripple analysis, not a single curve.

Frequently asked questions

What is the RC time constant?

τ = R × C seconds — the time to charge to 63.2% (or discharge to 36.8%). After 5τ the circuit is 99.3% settled, the practical 'done' milestone.

How long does a capacitor take to charge?

Mathematically never 100%; practically 5τ ≈ 99.3%. A 10 kΩ/10 µF pair: 0.5 s. Solve exact targets with t = −τ·ln(1 − V/V₀).

Related tools

Technical references