kVA to Amps Calculator

Enter power as kVA, kW or hp and get the current for single or three-phase, with the kW/kVA conversion made explicit and the formulas documented.

kVA to Amps Calculator inputs

Used when converting kW or hp; ignored for kVA input.

Last updated: 2026-09-15

How the calculation works

  • kVA input is used directly; kW and hp are first converted to kVA through the power factor (hp at 746 W each).
  • Single-phase divides kVA by voltage; three-phase divides by √3 times voltage.
  • The result also shows real and apparent power so the PF conversion is visible.

Formula

Single-phase: I = kVA × 1000 / V
Three-phase:  I = kVA × 1000 / (√3 × V)
kW → kVA: kVA = kW / PF        hp → kVA: kVA = hp × 0.746 / PF
Formula variables
SymbolMeaningUnit
ILine currentA
SApparent powerkVA
VLine-to-line voltageV
PFPower factor

Worked example

A 10 kVA three-phase load at 400 V draws 10,000 / (1.732 × 400) = 14.4 A per line. The same 10 kVA single-phase at 230 V would draw 43.5 A — the reason three-phase is preferred for larger loads.

Interpreting the result

The result is the line current a balanced load draws at steady state. Use it for breaker sizing (with the applicable code multipliers), transformer loading checks and generator sizing. For motors, prefer nameplate FLA or NEC tables — the conversion here assumes the entered power is the electrical input.

Assumptions

  • Balanced three-phase load, sinusoidal conditions.
  • hp values are mechanical output power converted at 746 W per hp with the entered power factor.

Limitations

  • Does not include motor inrush, harmonics or unbalance.
  • Transformers are sized by kVA, but their actual loading also depends on the load's power factor.

Frequently asked questions

How many amps is 10 kVA at 240 V single-phase?

10,000 / 240 = 41.7 A. At 480 V three-phase it would be 1000 / (1.732 × 480) = 12.0 A.

Why does power factor matter?

kW is the real work; kVA is what the wires must carry. At PF 0.8, delivering 8 kW requires 10 kVA of current capacity. Low PF therefore increases conductor and breaker sizes for the same useful power.

Related tools

Technical references