Power Factor Correction Calculator

Enter load kW, current PF and target PF to get the capacitor bank size in kVAR, the kVA capacity you free up and how much line current drops.

Power Factor Correction Calculator inputs

Used for the current-reduction figures.

Last updated: 2026-09-15

How the calculation works

  • The tool converts both power factors to phase angles and takes the difference of their tangents.
  • That tangent difference times the real power gives the reactive kVAR the capacitor bank must supply.
  • It then shows the kVA before and after — the freed capacity in transformers and cables — and the line current reduction.

Formula

kVAR = kW × (tan φ₁ − tan φ₂)
φ = arccos(PF)
kVA = kW / PF
Formula variables
SymbolMeaningUnit
kVARReactive power to addkVAR
kWReal power of the loadkW
φ₁, φ₂Phase angles before and after correction°

Worked example

A 50 kW load at PF 0.75 draws 66.7 kVA. Correcting to 0.95 needs 50 × (0.882 − 0.329) = 27.6 kVAR. After correction the load draws 52.6 kVA and line current falls by 21% — meaningful capacity released in the same cables.

Interpreting the result

Correcting PF does not reduce the energy the load consumes; it reduces the reactive current the supply must carry. Benefits appear as lower demand charges, less voltage drop, freed transformer capacity and lower I²R losses. Most utilities penalize below 0.90–0.95; correcting beyond ~0.95 yields little and risks overvoltage at light load.

Assumptions

  • Steady, linear load — motors and transformers, not harmonic-rich drives.
  • Correction applied at the load or distribution board, not the utility meter.

Limitations

  • Loads with variable PF need an automatic capacitor bank with a PF controller, not one fixed bank.
  • Harmonic-rich environments (VFDs, rectifiers) require detuned/filtered capacitors to avoid resonance.
  • Do not size capacitors for a motor larger than recommended by NEC 460 — overcorrection can cause self-excitation.

Frequently asked questions

What is a good power factor?

0.95 is a common target: most utility penalties start below 0.90–0.92, and gains above 0.95 are small compared with the capacitor cost.

Does correcting power factor save energy?

It saves a little — the I²R losses in your cables drop with the current — but the main financial benefit is avoiding reactive demand charges and freeing installed capacity.

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Technical references